ChessProblems.ca Bulletin 4, December 2014.pdf

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CHESSPROBLEMS.CA
Contents
.
ISSUE 4 (DECEMBER 2014)
Page
1 Originals
97
2014 Informal Tourney . . . . . . . 97
Hors Concours . . . . . . . . . . . . 103
2 Articles
104
Arno T¨ngler:
u
Series Auto-
Stalemate Tasks . . . . . . . . 104
S´bastien Luce: AUW in Series-
e
Movers With Neutral Pieces
and One Fairy Condition . . . 111
3 Announcements
118
4 Selected Compositions
119
Series Reexmates . . . . . . . . . . 119
5 Recently
Honoured
Compositions
Canadian
120
6 Last Page
124
Apprenti Sorcier . . . . . . . . . . . 124
Editor:
Originals:
Articles:
Correspondence:
Cornel Pacurar
originals@chessproblems.ca
articles@chessproblems.ca
bulletin@chessproblems.ca
Attacking Line
[Drawing with charcoal and watercolour painting,
c
Elke Rehder, http://www.elke-rehder.de. Reproduced with permission.]
.....
ISSN 2292-8324
ChessProblems.ca
Bulletin
IIssue
4I
ORIGINALS
ChessProblems.ca’s annual Informal Tourney
is open for series-movers of any type and
with any fairy conditions and pieces.
Hors
concours
compositions (any genre) are also
welcome!
Send to: originals@chessproblems.ca.
2014 Informal Tourney
T195
Paul R˘ican
a
dedicated to the memory of
Dan Meinking
T196
Ladislav Packa
Daniel Novomesk´
y
T197
Arno T¨ngler
u
dedicated to Hanspeter Suwe
T192b
Paul R˘ican
a
2014 Judge:
Nicolas Dupont
2014 Tourney Participants:
1. Alberto Armeni
2. Geo Foster
3. Harald Grubert
4. Georgi Hadˇi-Vaskov
z
5. Joost de Heer
6. Emil Klemaniˇ
c
7. Branko Koludrovi´
c
8. V´clav Kotˇˇovec
a
es
9. Juraj L¨rinc
o
10. S´bastien Luce
e
11. Dan Meinking
†
12. Karol Mlynka
13. Daniel Novomesk´
y
14. Ladislav Packa
15. Cornel Pacurar
16. Paul R˘ican
a
17. George P. Sphicas
18. Adrian Storisteanu
ˇ uˇ
19. Jaroslav St´n
20. Pierre Tritten
21. Arno T¨ngler
u
22. Kjell Widlert
(FRA)
(ITA)
(AUS)
(DEU)
(MKD)
(NLD)
(SVK)
(HRV)
(CZE)
(SVK)
(FRA)
(USA)
(SVK)
(SVK)
(SVK)
(CAN)
(ROU)
(USA)
(CAN)
(SVK)
(FRA)
(DEU)
(SWE)
phser-dia 63
£¡
0
¢0
¥¢
! 5
 4
£
0
!
 
2¡#¡
(14+8) aser-s= 27
0
0
 #
0
#
5
(2+7) ser-s= 26
305
0
3#0
   
2
!
0
5
 32 #
£
(5+11) ser-h# 14
#"
!
0
#
0
5
C+ (5+6)
T198
Alberto Armeni
T199
Karol Mlynka
T200
Karol Mlynka
T201
Karol Mlynka
pser-h# 5
Circe
2 Solutions
C+ (7+5) ser-h# 5
C+ (1+3) ser-hs# 4
C+ (3+4) pser-h# 6
C+ (1+8)
Mirror Circe Turncoats
Black Super-Transmuting King Mirror Circe Turncoats
Sentinelles
b)
b8→e2
Sentinelles
White Super-Transmuting
b) - f3
King
b)
e1→d2 c)
e1→h4
ChessProblems.ca
Bulletin
IIssue
4I
December 2014
http://Bulletin.ChessProblems.ca
97
ORIGINALS
T192b:
T192 was cooked by Thierry Le
Gleuher and this is a new version provided by
the author.
T192b:
Circuit Bc1, impostor Rh1.
(Author)
T195:
One of the last of my problems seen
by Dan, which I was going to dedicate to him.
(Author)
T196:
Excelsior x 4, stalemate using three
pins.
(Authors)
T199, T200:
Super-Transmuting King
(Pressburger King):
King which denitively
takes up the nature of the checking piece
(and thus loses his royal status).
T206:
Virtual AUW (after 5.b6-b7 the virtual
capture of the bK is related every time to a
dierent white promotion), virtual Phoenix,
returns.
(Authors)
T207:
AUW, all promotions on d1, no
captures.
(Author)
T208:
AUW+1, all promotions on d1, no
captures by either side.
(Author)
T202
Harald Grubert
ser-h= 9
C+ (1+2) ser-h= 14
C+ (1+2) ser-h# 6
C+ (1+1+3) ser-h# 6
C+ (1+1+3)
Circe Equipollents
Circe Equipollents
b)
h8→
b)
h1→a1
NoWk
NoWk
= N. Double-Grasshopper
= Neutral Sparrow
b)
c7→c1 c)
d5→d3
2 Solutions
= Neutral Rook
= Neutral Pawn
= Moose
d)
d5→e3
= Rose Hopper
= Moose
= Double-Grasshopper
j
t
5
t
t
T203
Harald Grubert
g
T204
Harald Grubert
5'
¥
© ¨
T205
Harald Grubert
D
#¦
D
D
t
t
©
D
¦
T206
Ladislav Packa
Emil Klemaniˇ
c
ser-h# 5
AntiCirce
4 Solutions
4 
00#00
2¡¤¢£
T207
George P. Sphicas
C+ (8+7) ser-hxz 18
#
¢
 
0
£
¡ 0
T208
George P. Sphicas
(5+6) ser-hxz 25
#
0¢
 
0
£
0
T209
George P. Sphicas
dedicated to Phil
(5+7) ser-hxz 32
#¢
 0
0
 ¡0
1
(6+8)
ChessProblems.ca
Bulletin
IIssue
4I
December 2014
http://Bulletin.ChessProblems.ca
98
ORIGINALS
T209:
Promotions
. AUW+2,
possibly new task for this stipulation. Shields
to both kings, choice of some promotions
and destination squares not too obvious.
Without a2, Q to a1 via a4 before Ba4.
wPa2 does not need to be captured, since
the stipulation would allow it to be in the
neighborhood of the bK, but all black men
need to be packed in the SW corner.
(Author)
T210:
Circe Mutant Grasshopper: like Circe,
but after rebirth the piece transforms into
Grasshopper.
T215:
New overall length record for Circe
series-helpstalemate with normal force! The
previous record had 188 moves (see PDB
P1226974 for explanation).
(Authors)
T216:
There is just one possibility to add
the pair of
uncaptures, but that would
require a less-than-indeal twin (from b):
f7→d4 and h6→h7)
(Author)
T210
S´bastien Luce
e
dedicated to Maryan Kerhuel
1b & ser-= 28
C+ (1+8) ser-h# 106
C+ (16+1) 1b & ser-= 33
C+ (1+16) ser-= 52
Circe Mutant Grasshopper
Diagram AntiCirce
Antipodean AntiCirce
Malec Circe
10 2
0¥
T211
S´bastien Luce
e
dedicated to Chris Feather
¤
5
   
!¥
£
¢
T212
S´bastien Luce
e
0
0¥0
2 0
51
¥
 5
¥
c)
T213
S´bastien Luce
e
3
1
0
0
00
# 3 2
¥
C+ (1+15)
T214
S´bastien Luce
e
 
T217:
uncaptures in just four
moves. Probably the only position with this
stipulation and material that accommodates
this task.
(Author)
¤¤
ser-= 45
Frankfurt Chess
01
 
¥0
0 3
21
T215
Branko Koludrovi´
c
Arno T¨ngler
u
C+ (2+14) ser-h= 204
Circe
0  £¢
0
  
3#
!
2
T216
Branko Koludrovi´
c
T217
Cornel Pacurar
(15+11) -2w & !=1
b)
e8→f5
 
(2+1) -4w & !=1
f7→e6
(2+1)
ChessProblems.ca
Bulletin
IIssue
4I
December 2014
http://Bulletin.ChessProblems.ca
99
ORIGINALS
T220:
By all accounts, the regular (garden-
variety) series-mover is rather tedious.
Inequitable too: it has one side play all the
moves while the other just looks on passively.
This is not what a
series
should be all
about! The parry-series stipulation breaks the
monotony, introducing a modern dynamics
to the old genre. Here the series player is
allowed to check at any time, which the other
side must immediately parry, after which the
series continues (as if nothing happened).
This way both parties get to play an active
role in the solution.
The accent in this problem is on the
visual, rather than strictly chess-composition
thematic elements. The white king is nobly
uplifted whilst the black knight is tracing an
elaborate holiday-tree (NB both seasonable
and
reasonably PC) -like pattern.
An
unrelenting bS zigzag and a straight-line
wK march, made possible by both the
parry
series attribute and the knight’s colour-
changing, quirky moving manner. (In the
heavy theoretical tomes it will, presumably,
be identied as a rather decent specimen of
wenigsteinerschwarzespringerzickzacker
(and,
one hopes, it will be (diligently) illustrated
accordingly).)
Dan Meinking’s p.104
Probleemblad
68, 07-
09/2010 (Ka4 Ra3 / Kh1 Sg1 Pg5, pser-h= 9
– 1.Se2 2.Sc3+ Kb4 3.Sd5+ Kc4 4.Se3+ Kd4
5.Sf5+ Ke4
T218
Branko Koludrovi´
c
ser-h=% 24
C+ (2+2) ser-sF 58
C+ (2+3) pser-h= 8
Circe
W & B Minimummer
Black Minimummer
0 ¥
"
5
T219
Branko Koludrovi´
c
#
4
T220
Adrian Storisteanu
1 ¥
T221
Cornel Pacurar
C+ (2+2) 1w & ser-h##6 C+ (1+1+1)
3 Solutions
= Neutral Berolina
Superpawn
#
B
B
T222
Cornel Pacurar
ser- bare black
C+ (1+8)
king in 86
Chameleon Circe
Diagram AntiCirce
White Minimummer
White Randz¨ger
u
, , ,
= No-capturing
4335
#
T192b (Paul R˘ican):
a
1.f4 2.f5 3.f6 4.f×g7 5.g×h8=R 6.R×h7 7.Rh4 8.Rb4 9.h4
10.h5 11.h6 12.h7 13.h×g8=B 14.Bh7 15.Be4 16.Bc6 17.e4
18.Ke2 19.Kd3 20.Kc4 21.Kb5 22.Bc4 23.Se2 24.Qg1 25.Q×a7
26.Q×a8 27.Qa3 28.Qc3 29.a4 30.a5 31.a6 32.a7 33.a8=S
34.Sb6 35.S×d7 36.S×f8+ Sd7 37.Sh7 38.Sf6+ Kf8 39.Rh8+
Kg7 40.Re8 41.Sg8+ Sf6 42.Qg3+ Bg4 43.d3! 44.Bh6+ Kg6
45.Bf8 46.Sf4+ Kg5 47.Se6+ f×e6 48.Qh4+ Kf4 49.g3+ Kf3
50.e5+ Se4 51.Qf6+ e×f6 52.Sd2+ Ke3 53.Bc5+ Qd4 54.Bc4-d5
55.Sc4+ Kf3 56.Rf1+ Qf2 57.Be3 58.Bc1 59.Sd2+ Ke3 60.Sf3+
Qd2 61.Sh2 62.Re1+ Be2 63.Rh1
T195 (Paul R˘ican):
a
1.Kf4 2.Kg4!+ Bb7 3.Kg5!+ h5 4.Kg4!+ h4 9.Kg8!+ Qh6
12.Kf5!+ g5 13.Kf6!+ g6 14.Kg7!+ Qh5 17.Kf4!+ g4 18.Kf5!+
g5 19.Ke4!+ Bc8 20.b×a6 21.a7 22.a8=Q 23.Qa7 26.Kg3!+ h3
27.Qg1+ K×g1 =
T196 (Ladislav Packa & Daniel Novomesk´):
y
1.c4 6.a8=R 8.Re3 12.d×e7 13.e8=S 14.S×f6 15.Se4 19.c8=B
20.B×g4 21.Bf5 25.g×f7 26.f8=Q+ R×f8=
ChessProblems.ca
Bulletin
IIssue
4I
December 2014
http://Bulletin.ChessProblems.ca
100

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