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9. Using

f λ,

we ﬁnd the length of one cycle of the wave is

= 350/500 = 0.700 m = 700 mm. From

= 1/T , we ﬁnd the time for one cycle of oscillation is

= 1/500 = 2.00

−3

s = 2.00 ms.

(a) A cycle is equivalent to 2π radians, so that

π/3

rad corresponds to one-sixth of a cycle. The

corresponding length, therefore, is

λ/6

= 700/6 = 117 mm.

(b) The interval 1.00 ms is half of

and thus corresponds to half of one cycle, or half of 2π rad. Thus,

the phase diﬀerence is (1/2)2π =

rad.